So horizontal pulling force = 33.9sin55° = 27.77 N
Net force = pull - friction = 13.56 N
Net work = net force * displacement = 210 J
Or, suppose no initial velocity
acceleration = Fnet / m
Speed achieved = root(2*a*d)
Work done = final kinetic energry = m*v^2 / 2 = 210 J
A custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55 degree angle, against a 14.2 N friction force. Find the total work done on the vacuum.
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