rectangular polygon? not sure what that is....
if so it means the sides are 10/root2
area of 50. (its a square)
Whats the area of a rectangular polygon with one diagonal equal to 10 " and the other diagonal equal?
whats the area of a rectangular poligon with one diagonal equal to 10 " and the other diagonal equal to 10"?
- area=1/2 d1*d2
=50 square inches00
- Rectangular polygon with equal diagonals means that it is symmetric, so you need to find the lengths of 2 sides.
Rectangular also implies right angles at the corners.
A 10" diagonal can be extrapolated as part of a 3-4-5 right triangle - as it is the hypotenuse and a factor of 5. Apply the same factor to the other two dimensions (3 and 4), and we have sides of length 6 and 8 on a rectangle.
48 sq in in area.00
- At least 1 more piece of data is needed.
If all sides are equal,then 2a^2=100
- Rectangular polygon??
Wouldn't it be simpler to call it a rectangle.
Anyway, all rectangles have 2 diagonals that are equal... always...every time
The length of rectangle can be found from length of two sides using Pythagorean Theorem.
So if you have a rectangle with side lengths 6 and 8, then diagonals are:
d = √(6²+8²) = √(36+64) = √100 = 10
But if you have a rectangle with side lengths 2.8 and 9.6, then diagonals are:
d = √(2.8²+9.6²) = √(7.84+92.16) = √100 = 10
So here we have 2 rectangles with different side lengths, but with 2 diagonals with length 10
First rectangle has area = 6 * 8 = 48 sq inches
Second rectangle has area = 2.8 * 9.6 = 26.88 sq inches
So this question does not have enough information.
Perhaps question actually asked "What is area of REGULAR rectangular polygon with diagonal = 10?"
In this case we are dealing with a square. We can calculate side length (s) using Pythagorean theorem:
s² + s² = 10²
2s² = 100
s² = 50
But area of square is s²
So area of REGULAR rectangular polygon with diagonal = 10 inches is
A = s² = 50 sq inches00
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